What is 6(r-4) 2(r-8) plus 3r?

Answer 1

To simplify the expression ( 6(r-4) + 2(r-8) + 3r ), start by distributing the terms:

1. ( 6(r-4) = 6r - 24 )
2. ( 2(r-8) = 2r - 16 )

Now combine these with ( 3r ):

[ 6r - 24 + 2r - 16 + 3r = (6r + 2r + 3r) + (-24 - 16) = 11r - 40. ]

Thus, the final result is ( 11r - 40 ).