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Can you write the equation of a parabola that doesn't cross the x-axis in factored form?
Wiki User
∙ 11y ago
No.
Wiki User
∙ 11y ago
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Where does the parabola cross the x axis?
Set y = 0 and solve for x, with a parabola you should get one, two, or no x-axis crossings, it depends on the equation and the location on the x-y axis of the parabola.
Would the cross section of a satellite dish be modeled by a linear or a quadratic equation?
The satellite dish is a parabolic reflector. A parabola cannot be modeled by a linear equation because a linear equation is one that graphs as a straight line. It takes a second degree expression to plot it, and that means a quadratic equation.
When do you cross multiply to solve an equation?
When doing fractions, you may cross multiply.
Why does b represent the y-intercept?
B is just a constant variable. In the standard form for the equation of a line y= ax +b. When x = 0, this is where we cross the y axis and the equation evaluates to b.
What is the greatest number of real roots a polynomial of degree 2 can have?
A real root is when a quadratic equation, or the graph of a polynomial, crosses the x axis, or when the y coordinate is equal to 0. On any polynomial to the degree of two, when graphed the line follows a smooth arc in the shape of a "U" or and upside down "U". Since there are only two prongs to the parabola, or arc, it can only cross the x axis twice, if at all. So there can only be 2 real roots.
Where does the parabola cross the x axis?
Set y = 0 and solve for x, with a parabola you should get one, two, or no x-axis crossings, it depends on the equation and the location on the x-y axis of the parabola.
When does a parabola always cross the x-axis twice?
If the equation of the parabola is represented byy = ax^2 + bx + c then it crosses the x-axis twice if and only if b^2 > 4ac
Where do you find the roots when looking at a parabola?
-- The roots of a quadratic equation are the values of 'x' that make y=0 . -- When you graph a quadratic equation, the graph is a parabola. -- The points on the parabola where y=0 are the points where it crosses the x-axis. -- If it doesn't cross the x-axis, then the roots are complex or pure imaginary, and you can't see them on a graph.
If the discriminant is negative the graph of a quadratic function will cross or touch the x-axis time s?
If the discriminant is negative, the equation has no real solution - in the graph, the parabola won't cross the x-axis.
An equilateral triangle is inscribed in a parabola with its vertex at the vertex of the parabola how do you find the length of the equilateral triangle?
First you need more details about the parabola. Then - if the parabola opens upward - you can assume that the lowest point of the triangle is at the vertex; write an equation for each of the lines in the equilateral triangle. These lines will slope upwards (or downwards) at an angle of 60°; you must convert that to a slope (using the tangent function). Once you have the equation of the lines and the parabola, solve them simultaneously to check at what points they cross. Finally you can use the Pythagorean Theorem to calculate the length.
Would the cross section of a satellite dish be modeled by a linear or a quadratic equation?
The satellite dish is a parabolic reflector. A parabola cannot be modeled by a linear equation because a linear equation is one that graphs as a straight line. It takes a second degree expression to plot it, and that means a quadratic equation.
Why doesn't an equation cross the x-axis when it cannot be factored?
Since I can't show you graphs on Answers I must ask you to visualise a parabola that does cross the x-axis at two points. (It doesn't matter whether the parabola is 'open' at the top or at the bottom.) For example, we could consider the parabola5x2 + 9x - 2We find that it crosses the x-axis at x = 1/5 and x = -2. We call these solutions or roots of5x2 + 9x - 2 = 0, and we can show that each of these solutions can be used to create a factor of the original parabola.x = 1/5 yields the factor x - 1/5 :which we demonstrate by dividing 5x2 + 9x - 2 by x - 1/5 to get 5x + 10 even (and we can check that x - 1/5 multiplied by 5x + 10 yields the original parabola).x = -2 yields the factor x + 2 :which we again demonstrate by dividing 5x2 + 9x - 2 by x + 2 to get 5x - 1 even.The point of this is that when a parabola crosses the x-axis it has solutions that yield factors. However, if it doesn't cross the x-axis it cannot have solutions (because it cannot 'equal' zero), and therefore cannot be factored.
Why is a quadratic graph shaped that way?
because there are usually two intercepts for that type of equation, so the line must cross over the x axis twice. the parabola is the only shape that complies with my earlier statement.
Purpose of finding the area of a parabola?
If you needed to calculate say, the volume of a gutter, it would be the AREA of the cross-section (parabola) multiplied by the length of the gutter.
Using the discriminant how many times does the graph of this equation cross the x axis 3x2 plus 6x plus 20?
In this case, the discriminant is less than zero and the graph of this parabola lies above the x-axis. It never crosses.
Can a cross protect me from a ghost?
i guess cross doesnt have an effect on ghost...
What is the tilted away cross section of a cone?
Depends on the way you cut the cone, but the outline is either an ellipse or a parabola.
