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5x2 + x - 6 = (5x + 6)(x - 1) 5x2 - x - 6 = (5x - 6)(x + 1)
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Factor the following 5x2-5?
5(x + 1)(x - 1)
How do you factor out -5x's plus 9X-4?
As written, -5x + 9x = 4x 4x - 4 = 4(x - 1) If that's -5x2 + 9x - 4, that factors to -(x - 1)(5x - 4)
How do you factor x squared - 6x?
x2 - 6x = (x*x - 6*x) = x*(x-6)
Factor x2 equals -5x-6?
x2 - 5x - 6 = x2 - 6x + x - 6 = x(x - 6) + 1(x - 6) = (x - 6)(x + 1)
What is the answer to factor the following polynomial x to the second power minus one?
(x + 1)(x - 1)
Factor the following 5x2-5?
5(x + 1)(x - 1)
What is the factor of 5x2-36x plus 36?
(x - 6)(5x - 6)
Solution 5x2 plus 29x - 6?
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)
What is the factor of 5x2 - 16x plus 12?
(5x - 6)(x - 2)
What is each factor as a polynomial in descending order 5x2 - 16x plus 12?
5x2 - 16x + 12 = 5x2 - 10x - 6x +12 = 5x(x - 2) - 6(x - 2) = (x - 2)(5x - 6) Whether or not these are in descending order depends on the value of x.
Factor the trimomial 5x2-21x plus 18?
(5x-6)(x-3)
Factor the trinomial 5x2 plus 29x-6 enter each factor as a polynomial in descending order?
(5x - 1)(x + 6)
What is the factor of 3x3 5x2 - 6x 18?
(x + 3)(3x^2 - 4x + 6)
How do you factor 5x2 plus 20x?
5x2 + 20x = 5x (x + 4)
Factor the trinomial and enter your answer below Write each factor as a polynomial in descending order 5x2 - 16x plus 12?
5x2-16x+12 = (5x-6)(x-2) when factored
How do you solve equations x3 plus 5x2 equals 6x?
your equation is this... x3 + 5x2 = 6x get all the terms on the left side x3 + 5x2 - 6x = 0 now factor out an "x" x(x2 + 5x - 6) = 0 now factor the equation inside x(x + 6)(x - 1) from this you can find your x-values x= 0, -6, and 1 now that you have your x-values your equation is solved. just use algebra to get all of the terms on the one side. then factor out anything that is common in all of the terms. then factor the polynomial. then find what values for "x" that satisfy the equation.
How do you factor 5x2 - 4x?
x(5x - 4)
