5(x + 1)(x - 1)
x2 - 6x = (x*x - 6*x) = x*(x-6)
As written, -5x + 9x = 4x 4x - 4 = 4(x - 1) If that's -5x2 + 9x - 4, that factors to -(x - 1)(5x - 4)
NO!!! 42 is a multiple of '6'. ( 6 x 7 = 42) However, 6 is a factor of 42.
x2 - 5x - 6 = x2 - 6x + x - 6 = x(x - 6) + 1(x - 6) = (x - 6)(x + 1)
5(x + 1)(x - 1)
(x - 6)(5x - 6)
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)
(5x - 6)(x - 2)
5x2 - 16x + 12 = 5x2 - 10x - 6x +12 = 5x(x - 2) - 6(x - 2) = (x - 2)(5x - 6) Whether or not these are in descending order depends on the value of x.
(5x-6)(x-3)
(5x - 1)(x + 6)
(x + 3)(3x^2 - 4x + 6)
5x2 + 20x = 5x (x + 4)
5x2-16x+12 = (5x-6)(x-2) when factored
your equation is this... x3 + 5x2 = 6x get all the terms on the left side x3 + 5x2 - 6x = 0 now factor out an "x" x(x2 + 5x - 6) = 0 now factor the equation inside x(x + 6)(x - 1) from this you can find your x-values x= 0, -6, and 1 now that you have your x-values your equation is solved. just use algebra to get all of the terms on the one side. then factor out anything that is common in all of the terms. then factor the polynomial. then find what values for "x" that satisfy the equation.
x(5x - 4)