Let's try and find one and that will answer the question. We don't need to finish the job of finding one, just to get to the point where we can say yes or no for sure.
Let the length be L and the width be W
2L+2W=22
LW=20
So L=20/W
Now substitute that into the first equation
Yes
2(20/W)+2W=22
40/W+2W=22
(40+2W2 )/W=22
22W=(40+2W2 )
This is a quadratic equation
2W2 -22W+40=0
or
W2 -11W+20=0
We don't need to solve the equation to answer the question.
The discriminant ((-11)2 -4(20)=41 which is positive so there are two real roots. That means two values for W.
This tells us there is rectangle with those dimensions.
8.7 and 2.3 are the approximate dimensions of the desired rectangle, in case you want to know.
To find the perimeter of a rectangle, you need more information than just the area. The area of a rectangle is calculated by multiplying its length by its width. Without knowing the specific dimensions of the rectangle, it is impossible to determine the perimeter. Additional information, such as the length or width of the rectangle, is required to calculate the perimeter.
What is a rectangle were the area is 10 and the perimeter
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
The greatest area for a fixed perimeter will be when all the sides are equal or when the rectangle approaches the shape of a square.
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
26 cm
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
The perimeter of a rectangle cannot be determined with the area alone as the lengths could vary. For example, the perimeter of the rectangle could be 12 (1 and 5) or 9 (2 and 2.5). For both cases, the area is still 5cm2, but the length can still change to result in different results.
Would be congruent.It doesn't have to be a rectangle, though.It could be any shape.
No. For example, a 4x1 rectangle will have an area of 4 and a perimeter of 10. A 2x2 rectangle will have the same area of 4, but a perimeter of 8.
The perimeter of the rectangle is the sum of its 4 sides.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
yes, for example:a 4 by 5 rectangle has an area of 20 and a perimeter of 18a 2 by 7 rectangle has an area of 14 and a perimeter of 18yes, for example:
Yes, the perimeter or area of a rectangle can be an irrational number. Thanks