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Cube root of 1728

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Anonymous

16y ago
Updated: 4/28/2022

12

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16y ago

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Related Questions

What is the cube of 1728?

The cube root of 1728 is: 121728 cubed is: 5,159,780,352


What is the odd cube number of 1728?

1728 is even so it cannot have an odd cube root.


What is a number cubed is 1728 what is the number?

the cube root of 1728 is 12


How is cube root 1728 equals 12?

Because 123 = 1728


What number multiplied by itself 3 times is 1728?

To find the number that, when multiplied by itself three times, equals 1728, you need to calculate the cube root of 1728. The cube root of 1728 is 12, since 12 × 12 × 12 = 1728. Therefore, the number is 12.


What number times itself three times equals 1728?

To find the number that, when multiplied by itself three times, equals 1728, we need to calculate the cube root of 1728. The cube root of 1728 is 12, since (12 \times 12 \times 12 = 1728). Thus, the number you are looking for is 12.


What is the cube root of 1728?

The Answer Is 12 12 x 12 x 12 = 1728 12 x 12 = 144 144 x 12 = 1728


What to the third power equals 1728?

x^(3) = 1728 so we take the 'third root' (cube root) ( sometimes shown as (3/x Hence x = 1728^(1/3) x = 12


What is the procedure to calculate the edge of a cube of volume 1728 cubic meters?

The volume of a cube is found by cubing the length of an edge. To find the measure of an edge of a cube of a known volume, simply find the cube root of the volume. In this case, the cube root of 1728 is 12. It's actually plus or minus 12, but we drop the minus 12 because shapes can have negative dimensions. Given a cube of known volume, the length of an edge can be found by finding the cube root of the cube's volume.


What is radical -1728 cubed?

The expression "radical -1728" refers to the square root of -1728, which is not a real number because you cannot take the square root of a negative number in the realm of real numbers. In the context of complex numbers, it can be expressed as ( \sqrt{-1728} = \sqrt{1728} i = 12\sqrt{12} i ). Cubing this value, ( (12\sqrt{12} i)^3 = 1728\sqrt{12^3} i^3 = -1728 \cdot 12\sqrt{12} = -20736\sqrt{12} ). Thus, the cube of the square root of -1728 is a complex number.


Find the cuberoot of 1728 by factor method?

Out of the factor pairs of 1728, only 144 and 12 have a square/square root relationship. 12 has to be the cube root of 1728. (1728,1)(864,2)(576,3)(432,4)(288,6)(216,8)(192,9)(144,12)(108,16)(96,18)(72,24)(64,27)(54,32)(48,36)


What is the cubic root of 1728?

It is 12 because 12*12*12 = 1728

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