x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
(2 sin^2 x - 1)/(sin x - cos x) = sin x + cos x (sin^2 x + sin^2 x - 1)/(sin x - cos x) =? sin x + cos x [sin^2 x - (1 - sin^2 x)]/(sin x - cos x) =? sin x + cos x (sin^2 x - cos^2 x)/(sin x - cos x) =? sin x + cos x [(sin x - cos x)(sin x + cos x)]/(sin x - cos x) =? sin x + cos x sin x + cos x = sin x + cos x
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
We write sin x * sin x = sin2 x
(x-2)^2+y^2=64
The amplitude of the wave [ y = -2 sin(x) ] is 2.
The amplitude is 4 .
The amplitude is 1.
y = sin(-x)Amplitude = 1Period = 2 pi
The amplitude of a function is half the distance between the maximum and minimum values. This is the absolute value of the number in front of the trig function. for example, y=Asin(x) or y= Acos(x) the absolute value of A is the amplitude. Therefore, the amplitude of y=-2sinx is 2
if you are studying a (simple) wave described by: x = A sin(kt) then A = amplitude
The amplitude is ' 1 ' .
5
Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
1. The amplitude of the graph y=sin(x) is equal to 1. 2. The amplitude of the situation was greater than he anticipated.
In order to solve this inhomogeneous differential equation you need to start by solving the homogeneous case first (aka when the right hand side is just 0). The characteristic equation for this differential equation is r²+1=0 or r²=-1 which means that r must be equal to ±i. Therefore, the general solution to this homogeneous problem Is y=c1*sin(x)+c2*cos(x) where c1 and c2 are constants determined by the initial conditions. In order to solve the inhomogeneous problem we need to first find the Wronskian of our two solutions. _________|y1(x) y2(x) | __| sin(x) cos(x) | W(y1, y2)= |y1'(x) y2'(x) | = | cos(x) -sin(x) | = -sin(x)²-cos(x)²= -1 Next, we calculate the particular solution Y(x)=-sin(x)* Integral(-1*cos(x)*cot(x)) + cos(x)*Integral(-1*sin(x)*cot(x)) =sin(x)*Integral(cos²(x)/sin(x)) - cos*Integral(cos(x)) =sin(x)*(ln(tan(x/2)) + cos(x)) -cos(x)*sin(x)=sin(x)*ln(tan(x/2)) Finally, to answer the entire equation, we add the particular solution to the homogeneous solution to get y(x)=sin(x)*ln(tan(x/2)) + c1*sin(x)+c2*cos(x)