250(x) = 400,000 Use logs to base '10' Hence log250^(x) = log400,000 xlog250 = log 400,000 Notirce how the power (x) becomes the coefficient. This is oerfectly correct under 'log' rules. x = log 400,000 / log 250 (NOT log(250/400,000). x = 5.60206 / 2.39794 x = 2.33619689..... ~ 2.33619 to 5 d.p.
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
Log (x^3) = 3 log(x) Log of x to the third power is three times log of x.
Here are a few, note x>0 and y>0 and a&b not = 1 * log (xy) = log(x) + log(y) * log(x/y) = log(x) - log(y) * loga(x) = logb(x)*loga(b) * logb(bn) = n * log(xa) = a*log(x) * logb(b) = 1 * logb(1) = 0
log(9x) + log(x) = 4log(10)log(9) + log(x) + log(x) = 4log(10)2log(x) = 4log(10) - log(9)log(x2) = log(104) - log(9)log(x2) = log(104/9)x2 = 104/9x = 102/3x = 33 and 1/3
Show that sec'x = d/dx (sec x) = sec x tan x. First, take note that sec x = 1/cos x; d sin x = cos x dx; d cos x = -sin x dx; and d log u = du/u. From the last, we have du = u d log u. Then, letting u = sec x, we have, d sec x = sec x d log sec x; and d log sec x = d log ( 1 / cos x ) = -d log cos x = d ( -cos x ) / cos x = sin x dx / cos x = tan x dx. Thence, d sec x = sec x tan x dx, and sec' x = sec x tan x, which is what we set out to show.
250(x) = 400,000 Use logs to base '10' Hence log250^(x) = log400,000 xlog250 = log 400,000 Notirce how the power (x) becomes the coefficient. This is oerfectly correct under 'log' rules. x = log 400,000 / log 250 (NOT log(250/400,000). x = 5.60206 / 2.39794 x = 2.33619689..... ~ 2.33619 to 5 d.p.
If y is a function of x, that is y=f(x), then the derivative of x-y is 1-y' or 1-dy/dx (where y' or dy/dx is the differential coefficient of y with respect to x).
Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1
cos(x) cot(x) = cos(x) * 1/(tan(x)) = cos(x) * 1 / (sinx(x) / cos(x)) = cos2(x) / sin(x) = (1-sin2(x)) / sin(x) = 1/sin(x) - sin(x) so the antiderivative of cos(x)cot(x) = log[abs(tan(x/2))]+cos(x) This can also be written as log[abs((sin(x)/(cos(x)+1))]+cos(x) if we want everything in terms of x and not (x/2). The two answers are, of course, the same. where log(x) refers to the natural log, often written ln(x). We might write ln[|sin(x)|/|cos(x)+1|] +cos(x)
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
In a ploynomial or differential equation or really any formula or equation with variables in it, the coefficients are the terms "in front of" the variable or multiplied the variables. Each variable generally has its own coefficient. If a coefficient is constant (ie just a number) then it is a constant coefficient. eg Consider the polynomial , 3x2+9yx+6 in terms of x. It has one constant coefficient (3), one variable coefficient (9y) and one constant (6).
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
tan(-x) = -tan(x)
The derivative of the natural log is 1/x, therefore the derivative is 1/cos(x). However, since the value of cos(x) is submitted within the natural log we must use the chain rule. Then, we multiply 1/cos(x) by the derivative of cos(x). We get the answer: -sin(x)/cos(x) which can be simplified into -tan(x).
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)