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What equation represents a line parallel to the graph of 2x - 4y equals 16?
2x-4y = 16 -4y = -2x+16 y = 1/2x-4 Any equation that has a slope of 1/2 but a different intercept of -4.
What is the vertex of the graph -2x2 16x -15?
Considering a general quadratic equation y=ax^2 + bx + c, the x coordinate of the vertex is found from the formula x= -b/2a and the y coordinate is found from putting that x coordinate back into the original quadratic equation which in this case I am assuming is y= -2x^2 + 16x -15. So, the x coordinate of the vertex is x=-16/(2*-2) = 4 To find the y coordinate we plug 4 back into y= -2x^2 + 16x -15 so we have y= -2 * 4^2 + 16*4 - 15. Following the order of operations we get y= -2 *16 + 64 - 15= 17 Therefore the vertex is at (4, 17).
3x plus 6y equals 48?
You could graph this Polynomial by using substution to solve for two points..which will define a line. If x=16, then y=0, If x=0, then y=8. Graph this line and you have the solution set for the equation.
What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
What is the graph of x radical x-16?
g(x) = √(x - 16) The graph of g(x) = √(x - 16) has the same shape as the graph of f(x) = √x. However, it is shifted horizontally to the right 16 units. The graph of the function f(x)=square root(x) is made up of half a parabola (in the first quadrant) with directrix (16, 0), which opens rightward. The domain is [16,∞) and range [0, ∞).
What equation represents a line parallel to the graph of 2x - 4y equals 16?
2x-4y = 16 -4y = -2x+16 y = 1/2x-4 Any equation that has a slope of 1/2 but a different intercept of -4.
What is the line of symmetry of the graph of the equation?
Answer this question… What is the line of symmetry of the graph of the equation ? A. x = -2 B. x = -4 C. x = -16 D. x = -8
The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
What is the vertex of the graph -2x2 16x -15?
Considering a general quadratic equation y=ax^2 + bx + c, the x coordinate of the vertex is found from the formula x= -b/2a and the y coordinate is found from putting that x coordinate back into the original quadratic equation which in this case I am assuming is y= -2x^2 + 16x -15. So, the x coordinate of the vertex is x=-16/(2*-2) = 4 To find the y coordinate we plug 4 back into y= -2x^2 + 16x -15 so we have y= -2 * 4^2 + 16*4 - 15. Following the order of operations we get y= -2 *16 + 64 - 15= 17 Therefore the vertex is at (4, 17).
What is the coefficient of the squared term in the parabola's equation when the vertex is at 3 5 and the point -1 6 is on it?
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (3, 5), and a point on it is (-1, 6) → 6 = a(-1 - 3)² + 5 → 6 = a(-4)² + 5 → 1 = 16a → a = 1/16 → The coefficient of the x² term is 1/16
How do you write an equation that represents the statement 10 percent of 160 is 16?
160 x 0.1 = 16
What does y equals 9 mean when x equals 16?
This is slightly out of context but you will have an equation of a graph we call it x and y because they are the axises we use on a graph. Usually in an equation we try to find the value of y. An equation that works in this case is y=x-7 but there are many others. But if we use the example i have given when x=16 this means y=16-7 which is 9 if you were to plot this point on a graph it would be 16 across the x axis and 9 up Hope this helps
What does 3k plus 16 equals 5k?
It represents an algebraic equation in the variable, k.
When vertex of this parabola is at (35) . When the y-value is 6 the x-value is -1. what is the coefficient of the squared term in the parabolas equation?
It is 1/16.
When you subtract one square number from another the answer is 16 what are the two squared numbers?
x2 -y2 =16 This is an equation that describes your problem. We can write this equation as (1/16)x2 -(1/16)y2 =1 You may recognize this as the equation whose graph is a hyperbola. So there are an infinite number of solutions.
What is the vertex of the graph of the function below y x2 - 8x plus 12?
To find the vertex of the quadratic function ( y = x^2 - 8x + 12 ), we can use the vertex formula ( x = -\frac{b}{2a} ). Here, ( a = 1 ) and ( b = -8 ), so ( x = -\frac{-8}{2 \cdot 1} = 4 ). To find the y-coordinate, substitute ( x = 4 ) back into the equation: ( y = 4^2 - 8 \cdot 4 + 12 = 16 - 32 + 12 = -4 ). Therefore, the vertex is at the point ( (4, -4) ).
How do u find the equation of the axis of symmetry and the vertex of the graph of each function for example y x2-8x-9 Plz help i need to know this?
To find the equation of the axis of symmetry for the quadratic function (y = x^2 - 8x - 9), use the formula (x = -\frac{b}{2a}), where (a = 1) and (b = -8). This gives (x = -\frac{-8}{2 \cdot 1} = 4). The vertex can be found by substituting this (x) value back into the original equation: (y = 4^2 - 8(4) - 9 = 16 - 32 - 9 = -25). Thus, the vertex is at the point ((4, -25)) and the axis of symmetry is the line (x = 4).
