x2+8= y
This equation represents a function. It will be a parabola with the vertex at (0,8).
You can easily graph this on a graphing calculator or from prior knowledge.
You know the basic graph of y=x2 with vertex (0,0) and opens upwards on the y-axis. From the equation, you simply shift the vertex vertically up 8 so the new vertex is (0,8)
This represents a function because for every x value there is one y value.
(x + 2)(x + 4) x = -2, -4
4x2 + x2 = 8 + x2
4x+8
x2 + 6x + 8 = (x + 4)(x + 2)
x2 + 7x - 8 = (x + 8)(x - 1)
x2+7x-8 = (x-1(x+8)
That is not a function, although it does involve the function of addition. A function is something that is done to numbers.
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
(x2 + 14 + 48 / (x + 8) = (x2 + 62) / (x + 8) =(x2 + 8x - 8x - 64 + 126) / (x + 8) = x - 1 + 126/(x+8)
x2 + 8x = x(x+8)
No. x2+5x is a polynomial, an algebraic expression or a formula, but it is not a function. It could be used to help define a function. {(x,y) | y = x2 + 5x , x any real number} is a function
The discriminant formula. b2 - 4ac 32 - 4(1)(8) 9 - 32 = - 23 ===========This shows no real roots to this function.