Answer: (x - 2)(x² + 2x + 4)Factor the difference of cubes:a³ - b³ = (a - b)(a² + ab + b² )note 8 = 2³ = 8 ⇒ b = 2 , with a = xSox³ - 8= x³ - 2³= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)
(3x + 8)(3x - 8)
8(d-3)
7g-10h
(2x + 5)(4x^2 - 10x + 25)
8(y - 1)(y^2 + y + 1)
8(y - 1)(y^2 + y + 1)
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
the answer is (3x-2)(9x squared+6x+4)
-4
9 minus 8
The expression n2 - n - 56 factors to (n - 8)(n + 7).
32a + 8= 8(4a+1)
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8 - (9 - t)
Answer: (x - 2)(x² + 2x + 4)Factor the difference of cubes:a³ - b³ = (a - b)(a² + ab + b² )note 8 = 2³ = 8 ⇒ b = 2 , with a = xSox³ - 8= x³ - 2³= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)
You could factor this as a difference of squares, but because 8 is not a perfect square, you would wind up with radicals in your answer: x2 - 8 = (x + √8)(x - √8) = (x + 2√2)(x - 2√2)