(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
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Answer: (x - 2)(x² + 2x + 4)Factor the difference of cubes:a³ - b³ = (a - b)(a² + ab + b² )note 8 = 2³ = 8 ⇒ b = 2 , with a = xSox³ - 8= x³ - 2³= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)
2(x + 4) or 2(x - 4) depending on the missing operational sign.
(3x + 8)(3x - 8)
8(d-3)
7g-10h