Q: How do you solve 4x2 plus 12x equals 0?

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There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.

4x2 is 8+ 12x + 3 collect like terms, 8+3= 11, 12x+11 to solve for x, transpose the 11 to the other side of the = sign, 12x=-11, divide by 12, x=-11/12

(2x + 3)(2x + 3)

4x2 + 12x + 5 = (2x + 1)(2x + 5).

4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).

4x2+12x = 4x(x+3) when factored

Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)

12x * 4x2 = 48x3

4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)

4x2+50x = 0 4x(x+12.5) = 0 x = 0 or x = -12.5

4(x + 2)(x + 1)

(2x+5)(2x+1)