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x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)

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Q: How do you factor x3 2x2 5x 4?
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Factor 2x2-5x plus 12?

2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)


How do you factor 2x2 plus 5x-12?

2X2+5x-12 4+5x-12 -8+5x 5x-8


What is the greatest common factor of 8x2 and 10x3?

Show the terms as additive here..., 8X2 + 10X3 factor out 2X2 2X2(4 + 5X) ---------------- 2X2 ==== greatest common factor


What is the factor of X3 - 2x2 - 4x plus 8?

x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)


How do you Factor x3 - 4x2 5x - 20?

x3 - 4x2 + 5x - 20 = x2*(x - 4) + 5*(x - 4) = (x2 + 5)*(x - 4)


How do you factor x3 plus 2x2 plus 4x plus 8?

(x + 2)(x^2+4)


How do you find the x- coordinates of the turning points of y equals x3-2x2-5x plus 6?

Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)


Factor completaly x3 plus 2x3 plus 4xplus 8?

If that's 2x2, the answer is (x + 2)(x2 + 4)


Factor x3 plus 3x2-6x-8?

x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)


How do you factor 12x4 plus 10x3-12x2?

You would first factor out anything that is common between the 3 parts. 2x2 is the greatest common factor. To pull out the 2x2, you divide each term by 2x2 like so:12x4/2x2=6x210x3/2x2=5x-12x2/2x2=-6We now know that 12x4+10x3-12x2= 2x2(6x2+5x-6)The next step involves using the "slip and slide" method for the trinomial inside the parentheses:6x2+5x-6x2+5x-36(x+9)(x-4)(x+9/6)(x-4/6)(x+3/2)(x-2/3)(2x+3)(3x-2)Remembering that the result for the slip and slide method only accounts for 6x2+5x-6 we must multiply (2x+3)(3x-2) by 2x2.Your final answer is 2x2(2x+3)(3x-2).


Factor x3 plus 2x2 -19x -20?

x3 + 2x2 - 19x - 20 = x3 + x2 + x2 + x - 20x - 20 = x2(x + 1) - x(x + 1) - 20(x + 1) = (x + 1)(x2 + x - 20) = (x + 1)(x - 4)(x + 5)


When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?

(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)