x3 - 4x2 + 5x - 20
= x2*(x - 4) + 5*(x - 4)
= (x2 + 5)*(x - 4)
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x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)
First factor is x, but we need to know the sign of 5x in your equation...
(x-2)(x+1)(x+5)
(x - 1)(x^2 - 5)
It is not possible to be sure about the answer because there is no sign before the linear term. If the polynomial is x3-4x2+x-4 then, the factors are (x-4) and (x2+1).