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How do you factor x cubed minus four x squared plus x plus 6?
x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)
How do you factor x3 plus 12x2 5x?
First factor is x, but we need to know the sign of 5x in your equation...
How do you factor x3 plus 4x2-7x-10 completely?
(x-2)(x+1)(x+5)
What is the factor of the polynomial x3-4x2 x-4?
It is not possible to be sure about the answer because there is no sign before the linear term. If the polynomial is x3-4x2+x-4 then, the factors are (x-4) and (x2+1).
How do you factor x3-x2-5x plus 5?
(x - 1)(x^2 - 5)
How do you factor 5x4 plus 20x3plus 45x equals?
5x is a common factor of all terms:- 5x(x3+4x2+9)
When dividing the polynomial x3 4x2 5x 2 by x 2 the remainder is 0 making x 2 a factor?
Yes, if there is no remainder after division, the divisor is a factor.
What is the factorization of the trinomial x3-4x2-45x?
X3 - 4X2 - 45XX(X2 - 4X - 45)=============X is only common factor here.
Factor x3 plus 4x2 plus x plus 4?
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
How do you factor x cubed minus four x squared plus x plus 6?
x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)
How do you factor x3 2x2 5x 4?
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
How do you factor x3 plus 12x2 5x?
First factor is x, but we need to know the sign of 5x in your equation...
What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
How do you factor x3 plus 12x2-5x?
x3 + 12x2 - 5x = x(x2 + 12x - 5) = x(x + 6 - √41)(x + 6 + √41)
How do you factor x3-4x2-20x plus 48?
(x - 2)(x + 4)(x - 6)
Is x-3 a factor of fxx3 4x2-11x-30?
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
How do you factor x3 plus 4x2 - 7x - 10 completely?
(x + 1)(x - 2)(x + 5)
