(5x + 2)(x + 3)
It is (x+6)(x+7) when factored
5x - 4 = 3x + 6 5x - 3x = 6 + 4 2x = 10 x = 5
6a -12b + 30 = 6 (a - 2b + 5)
5x-8= -2x+6(+8 = +8)5x=-2x+14(+2x = +2x)7x=14x=14
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
(5x + 2)(x + 3)
-4x2 + 5x + 6 = 0 Multiply through by -1: 4x2 - 5x - 6 = 0 (I prefer the leading coefficient to be >0) 4x2 - 8x + 3x - 6 = 0 4x(x - 2) + 3(x - 2) = 0 (x - 2)(4x + 3) = 0 So x - 2 = 0 or 4x + 3 = 0 ie x = 2 or x = -3/4
Factorise: 5x2 + 2x - 192 = (x - 6)(5x + 32) = 0; whence, x = 6 or -6.4.
1
y + 5x = 6 if x = {-1, 0, 1}
5x^2 + 6x - 2 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-3 plus or minus the square root of 19) divided by 5. x = 0.2717797887081348 x = -1.4717797887081348
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
Divide all terms by 4:- x2+5x-6 = (x-1)(x+6) when factored
what is 6 in 5x+6
(a + 6)(a + 4)
x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)