x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
6x(1+4)
(6x + 5)(6x - 5)
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
(x3)'=3x2(x3)''=(3x2)'=6x
3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)
-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)
6x(1+4)
(6x + 5)(6x - 5)
3x2 + 6x is ONE expression. A common factor is a factor that is COMMON to two (or more) expressions - not just one. An alternative answer: 3x can be factored out of both of those.
6x(3x2 - x + 4)
3x2 + 10x + 3 = (x + 3)(3x + 1).
3(x2 - 2x + 3)
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).