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Find 3 consecutive odd numbers where the product of the smaller two numbers is 46 less than the square of the largest number.?
Wiki User
∙ 7y ago
Let X be the first odd number, so X+2 will be the next odd number, and X+4 will be the final odd number. X * (X+2) = (X+4)2 - 46 X2+2X = X2+8X+16-46 X2+2X = X2+8X-30 Rearrange to get like terms to one side, 6X = 30 X =5 So the next two odd numbers would be 7 & 9 We can check the results: 5*7 =? 92 -46 35 =? 81-46 35 = 35 So the results are correct.
Consecutive odd means that there is a difference of 2 between each number and the next. If you call the smallest number x, the other two will be x+2, and x+4.
So, your equation will be: x(x+2) = (x+4)2 - 46.
Lenny Schumm
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