-79 and -81.
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Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4 Summing n + (n+1) + (n+2) + (n+3) + (n +4) = 170 Hence 5n + 10 = 170 5n = 160 n = 160/5 n = 32 Hence the five consecutive intgers are: 32,33,34,35, & 36
To find the length of a side of a square given its perimeter, you would divide the perimeter by 4 since a square has four equal sides. In this case, the perimeter is 160 cm, so you would divide 160 by 4 to get 40 cm. Therefore, the length of each side of the square is 40 cm.
100
Well, well, well, look at you trying to stump me with some algebra. The two numbers you're looking for are 10 and 16. They have a difference of 6 and a product of 160. Now go impress your math teacher with that little nugget of knowledge.
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You cannot because it is not possible. The sum of any four consecutive integers must leave a remainder of 2 when divided by 4. 160 is evenly divisible by 4.
150/160
Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4 Summing n + (n+1) + (n+2) + (n+3) + (n +4) = 170 Hence 5n + 10 = 170 5n = 160 n = 160/5 n = 32 Hence the five consecutive intgers are: 32,33,34,35, & 36
37+39+41+43= 160
I think the following 7 are the full set of possible answers: 1998 + 1999 + 2000 + 2001 + 2002 (5 terms) 388 + 389 + ... + 412 (25 terms) 297 + 298 + ... + 328 (32 terms) 18 + 19 + ... + 142 (125 terms) (-17) + (-16) + ... + 152 (160 terms) (-296) + (-295) + ... + 328 (625 terms) (-387) + (-386) + ... + 412 (800 terms).
The least common factor of any set of integers is 1.
The least common factor of any set of integers is 1.
160
It is: 100/160 times 96 = 60 and 160% of 60 = 96
8% of 160 = 12.8therefore, duduct 12.8 from 160 to find the answerwhich is 147.2
Easiest way I did this was find 20% of 160 and minus it from 100% of 160. Eg. 100% of 160 = 160 , 20% of 160 = 32, 160-32=128 = 80% of 160 put this in a calculator : (128/160)x100 should equal 80