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Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4 Summing n + (n+1) + (n+2) + (n+3) + (n +4) = 170 Hence 5n + 10 = 170 5n = 160 n = 160/5 n = 32 Hence the five consecutive intgers are: 32,33,34,35, & 36
10 and 16.
The perimeter of a square = side+side+side+side if 160=4xside then the side equals 40
100
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You cannot because it is not possible. The sum of any four consecutive integers must leave a remainder of 2 when divided by 4. 160 is evenly divisible by 4.
150/160
Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4 Summing n + (n+1) + (n+2) + (n+3) + (n +4) = 170 Hence 5n + 10 = 170 5n = 160 n = 160/5 n = 32 Hence the five consecutive intgers are: 32,33,34,35, & 36
37+39+41+43= 160
I think the following 7 are the full set of possible answers: 1998 + 1999 + 2000 + 2001 + 2002 (5 terms) 388 + 389 + ... + 412 (25 terms) 297 + 298 + ... + 328 (32 terms) 18 + 19 + ... + 142 (125 terms) (-17) + (-16) + ... + 152 (160 terms) (-296) + (-295) + ... + 328 (625 terms) (-387) + (-386) + ... + 412 (800 terms).
The least common factor of any set of integers is 1.
10 and 16.
The least common factor of any set of integers is 1.
160
The perimeter of a square = side+side+side+side if 160=4xside then the side equals 40
It is: 100/160 times 96 = 60 and 160% of 60 = 96