8x - 2y-120 = 0 subsitute the x with zero to find the y intercept 0x - 2y-120=0 -2y-120=0 -2y=120 y=60 substitue the y with zero to find the x intercept 8x-120=0 8x=120 x=120/8 x=15 lol hopefully i did this rite... sorry if i didnt XD i have a coordinate geometry test tomorrow... lol
80=4x, z=6x. find Z. x=80/4, x=20. z=6x20 z=120 answer= 120
y = 10x
X = 135 and y = 15 Solved by addition and substitution
160
We have the numbers x and y. x+y=120 x-y=50 2x=170 x=85 y=35
8x - 2y-120 = 0 subsitute the x with zero to find the y intercept 0x - 2y-120=0 -2y-120=0 -2y=120 y=60 substitue the y with zero to find the x intercept 8x-120=0 8x=120 x=120/8 x=15 lol hopefully i did this rite... sorry if i didnt XD i have a coordinate geometry test tomorrow... lol
200
If you meant 4x=3y-120 ==> 4x +120 = 3y ==> 4/3x+40=y In y=4/3x+40 4/3 is the slope (y will be increased by 4 when x is increased of 3) and +40 is the y intercept (when x is zero y is +40)
80=4x, z=6x. find Z. x=80/4, x=20. z=6x20 z=120 answer= 120
50
y = 10x
290
113
Maximum area for a rectangle of a given perimeter is a square so side would be 30m and area 900 sq m Math behind it: We have two variables X and Y (width and height) The perimeter of the rectangle is 120, therefore 2X + 2Y = 120 Now that we have an equation we can get rid of one of the variables like so: 2X + 2Y = 120 => 2Y = 120 - 2X => Y = 60 - X We want to optimize the area (A), which is X*Y: A = X * Y => Substitute the Y -> A = X * (60 - X) => A = 60X - X^2 To find the maximum area we'll have to find where the derivative A' zero. A = 60X - X^2 => Find the derivative -> A' = 60 - 2X A' = 0 => 60 - 2X = 0 => -2X = -60 => X = 30 Filling in the X to get the Y we get: Y = 60 - X => Y = 60 - 30 => Y = 30 Now that we have the X and the Y we can calculate the maximum area which is: X * Y => 30 *30 => 900
Assume that the two numbers are represented by 'x' and 'y': x+y=7 and xy= -120 As x+y=7, re-arrange the formula so that x=7-y Now substitute for x: (7-y)y = -120 7y-y2= -120 7y-y2+120 = 0 y2_7y-120 = 0 (y-15)(y+8) = 0 Therefore y = 15 or -8, and so putting back into the original equation, when y=15, x = -8, and when y= -8, x = 15
y+50 = 600 y = 600-50 y = 550