A sample equation could be y = 5/3x + 1, the x-intercept is 1 and the y-intercept is -1.
y = 8/49*x2
For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
What is the equation of the vertical line passing through (-5,-2)
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
y = 8/49*x2
For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
It is a straight line equation with no x or y intercepts on the Cartesian plane
What is the equation of the vertical line passing through (-5,-2)
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
The equation of a vertical line passing through the point (a, b) is x a.
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
the equation of a parabola is: y = a(x-h)^2 + k *h and k are the x and y intercepts of the vertex respectively * x and y are the coordinates of a known point the curve passes though * solve for a, then plug that a value back into the equation of the parabola with out the coordinates of the known point so the equation of the curve with the vertex at (0,3) passing through the point (9,0) would be.. 0 = a (9-0)^2 + 3 = 0 = a (81) + 3 = -3/81 = a so the equation for the curve would be y = -(3/81)x^2 + 3
The equation is x = 2
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