y=-5x+7
y=mx+b
m= slope
b= y-intercept
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
In the straight line equation of y = 3x+5 the slope is 3 and the y intercept is 5
y= slope + y-intercept
A normal slope-intercept form equation would read: y = mx + b The slope of an equation is also known as 'm'. The y-intercept would count as 'b'. So in a random equation such as: y= 5x + 6 '5' would be the slope and '6' would be the y-intercept.
You will need to find the slope and the y-intercept. For example: find the equation of the line containing points (0,5) and (2,10) and write it in slope-intercept form. The slope (m) here is found using the formula (y2-y1)/(x2-x1) So... (10-5)/(2-0) = 5/2 The y-intercept (b) is the value of y at the point where x=0 So... it is 5 The slope-intercept formula is y=mx+b So... that gives us y=(5/2)x+5
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
In the straight line equation of y = 3x+5 the slope is 3 and the y intercept is 5
y= slope + y-intercept
-1
A normal slope-intercept form equation would read: y = mx + b The slope of an equation is also known as 'm'. The y-intercept would count as 'b'. So in a random equation such as: y= 5x + 6 '5' would be the slope and '6' would be the y-intercept.
slope is 2 y intercept is 5/2
Since your equation is already in slope-intercept form, it's easy. Slope-intercept form is as follows: y=mx+b m always ends up being your slope, and b is your y intercept. Slope = 5, and the y intercept = 8 in your equation.
8
In order to find the slope and y-intercept we must first put the equation into slope intercept formula. This formula is y=mx+b where m=slope and b=y-intercept. Taking the equation 7x+2y=10 you can figure out the slope intercept formula of y=(-7/2)x+5. Given that information the slope is -7/2 and the y-intercept is 5.
13
y = -5x+2 in slope intercept form
5