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The slope with a line and intercept of the equation -6 and a slope of -5 would be -5. This is a math problem.

Q: Write the equation of a line that has a y-intercept of -6 and a slope of -5?

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The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.

y=2x+1

The answe iss..... 6

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You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

The equation of a line with an undefined slope is x = a.

Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation

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Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

Any vertical line has an undefined slope. The equation of the vertical line is x = a where the x-intercept is a.

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.

The equation for a line is y = mx + b, where m is the slope and b is the y-intercept.

As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6

y=-2x+3