2x + y = 4 (let x = 0 to find the y-intercept)
2(0) + y = 4
0 + y = 4
y = 4
2x + y = 4 (let y = 0 to find the x-intercept)
2x + 0 = 4 (divide both sides by 2)
x = 2
2x + y = 4 (to obtain another point let x = 1 and find the corresponding y-value)
2(1) + y = 4
2 + y = 4 (subtract 2 from both sides)
y = 2
Plot the three points (0, 4), (1, 2), and (2, 0) in a coordinate plane, and draw a line that passes through these points.
Graph the equation then find the x intercepts.
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
From the equation, the y intercept is simply determined by setting x = 0. The x intercept(s) are generally much harder to find: you will need to find the solutions of y = 0 [or f(x) = 0]. From the graph the intercepts are the coordinates of the points at which the graph crosses the axes.
x + 5y = 0Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides.x = -5yThis is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero.The only place on the graph where that is true is the origin. So the line goes through the origin,and the 'x' and 'y' intercepts are both zero.
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
Graph the equation then find the x intercepts.
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
From the equation, the y intercept is simply determined by setting x = 0. The x intercept(s) are generally much harder to find: you will need to find the solutions of y = 0 [or f(x) = 0]. From the graph the intercepts are the coordinates of the points at which the graph crosses the axes.
When y is 0 then x intercept is at (10, 0) When x is 0 then y intercept is at (0, -12)
You find the equation of a graph by finding an equation with a graph.
x + 5y = 0Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides.x = -5yThis is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero.The only place on the graph where that is true is the origin. So the line goes through the origin,and the 'x' and 'y' intercepts are both zero.
It is a line. There are many ways to graph it using intercepts etc. But, you can pick some x points, plug them in your equation, and find the corresponding y point, The graph those (x,y) values
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
To find x, sub 0 in for y. To find y, sub 0 in for x.y= -10, x= 4
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
by shoving it up your booty