19 and 34.
Let the two numbers be x and y; then:
x - y = 15
x + y = 53
Adding the two equations gives:
2x = 68 → x = 34
Substituting for x in the second gives:
34 + y = 53 → y = 19
Checking by substituting for x and y in the first gives:
34 - 19 = 15 as required.
22 and 26
=The Two numbers are 41 and 13.=
10 and 3
This is easily solved by using two equations in 2 unknowns and solving the system. x + y = 111 x - y = 43 If have not yet had the pleasure of studying algebra and the answer is important to you, you could hope the numbers are positive integers and try all pair of numbers whose sum is 43: 1,42 2,41 3,40 and so on, until you find a pair whose difference is 43.
The numbers are -16 and -15.
29 and 36
22 and 26
6 & 4
37 and 21
19 and 34
12 and 24?
20 & 3
18 and -6.
28 and 36
38-4=34
Find the 2 numbers whose difference is two and whose sum is 480.
That's not possible... * * * * * How about -5 and 25?