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Given two points on a graph with coordinates of X1,Y1 and X2,Y2, the slope of a straight line through the two points can be calculated as m=(Y1-Y2)/(X1-X2) The equation for the line can then be written as Y=mX+k, where k is some constant number. Note that m will be positive for lines that slant up from left to right, and negative for lines that slant up from right to left.
Once m is known, k can be found by substituting the values of X1 and Y1 into the equation and solving for k. When k is known, the value of the X axis intercept can be found by setting X to zero and solving the equation for Y. The Y axis intercept value can be found by setting Y to zero and solving for X.
Example: Let x1,Y1=6,4 and X2,Y2=2,2 Solve for m: m=(4-2)/(6-2)=2/4=1/2 Solve for k: Y=mX+k, 4=(1/2)6+k, k=4-3=1 If X=0, Y=(1/2)0+1=1 this is the Y axis intercept point If Y=0, 0=(1/2)X+1, 1/2X=-1, X=-2, this the X axis intercept point
What else can I help you with?
How do you find x with two points and a slope?
The slope is usually derived from the equation y = mx + b where m is the slope and b is the y-intercept. Slope: m = (y2 - y1)/(x2 - x1) As for finding intercepts, for finding the y intercept, look for the b in the equation or make x = 0, for x-intercepts, make y = 0.
How do you graph the line if y equals 3x plus 2?
you put the y intercept at 2, the x intercept at -2/3 and you join those two points.
How do you find the y-intercept of two points?
Say your two points are (-1,-2) and (3,4). Your y intercept is where the line your two points make crosses the y axis. You find this by taking one of your coordinates, (3,4) and you substitute it into the equation y = mx + c. y = mx + c 4 = 3x + c 4 - 3 = c c = 1 The first number in your coordinate is your x value and the second is your y value. (x,y)
What are the following points on the line given by the equation y 2x?
As Anand said, the question is vague. However, two important points for any equation are the x and y intercepts. For y = 2x, the x-intercept is (0,0) and the y-intercept is (0,0). Not sure if that helps.
The line whose equation is y equals 4x plus 2 has a y-intercept whose coordinates are?
When finding the y-intercept, plug in x=0 y = 4x + 2 y = 4(0) + 2 y = 2 So your intercept is (0,2)
How do you find Slope intercept equation of given two points?
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
How do you find x with two points and a slope?
The slope is usually derived from the equation y = mx + b where m is the slope and b is the y-intercept. Slope: m = (y2 - y1)/(x2 - x1) As for finding intercepts, for finding the y intercept, look for the b in the equation or make x = 0, for x-intercepts, make y = 0.
How do you use the y-intercept to graph a line?
The y-intercept identifies one point on a line. You need at least two points to determine a straight line.
How do you graph the line if y equals 3x plus 2?
you put the y intercept at 2, the x intercept at -2/3 and you join those two points.
How do you graph 3x-y equals -2?
The easy way is to plot the x- and y-intercept points and draw the lines that passes through those two points. If y = 0, then we have 3x = -2and x = -2/3. So the x-intercept point is (-2/3, 0). If x = 0, then we have -y = -2and y = 2. So the y-intercept point is (0, 2). Plot the points and draw the line.
Find intercept of y -25x plus y equals 65?
-25x+y=65-25(0)+y=65y=65When finding a y-intercept you replace the value of xwith 0. The same goes for finding the x-intercept, you replace the value of y with 0 and simplify the equation.
How do you find the y-intercept of two points?
Say your two points are (-1,-2) and (3,4). Your y intercept is where the line your two points make crosses the y axis. You find this by taking one of your coordinates, (3,4) and you substitute it into the equation y = mx + c. y = mx + c 4 = 3x + c 4 - 3 = c c = 1 The first number in your coordinate is your x value and the second is your y value. (x,y)
What is y intercept?
The y-intercept is the point on the graph which touches the y-axis (there can be multiple points).Algebraically, it would be at coordinates ( 0, f(0) ).The y intercept is where the line crosses the y axis
What is the slope intercept of the points -2 being the slope and -1 being the y-intercept?
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What are the following points on the line given by the equation y 2x?
As Anand said, the question is vague. However, two important points for any equation are the x and y intercepts. For y = 2x, the x-intercept is (0,0) and the y-intercept is (0,0). Not sure if that helps.
Y minus 4 equals 2x plus 1 in intercept form?
y - 4 = 2x +1y = 2x + 5The two intercept points are (0, 5) and (-5/2, 0)
How do you graph the equation y plus 5x equals -5?
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