As Anand said, the question is vague. However, two important points for any equation are the x and y intercepts. For y = 2x, the x-intercept is (0,0) and the y-intercept is (0,0). Not sure if that helps.
4
Points: (1, 5) and (2, 7) Slope: 2 Equation: y = 2x+3
The equation of: y = 5x-3 would satisfy the given conditions.
Suppose the equation of the line is y = mx + c where m and c need to be determined. The slope of the line = (difference in y-coordinates of the two given points)/(difference in x-coordinates of the two given points) = (-6 - 2)/(0 - 4) = -8/-4 = 2 So m = 2 ie the equation of the line becomes: y = 2x + c where c still needs to be determined. The point (0, -6) is on the line. That is, when x = 0, y = -6. Substituting in the equation, -6 = 2*0 + c so that c = -6 and the equation of the line is y = 2x - 6
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
(4,2), (2,1),(-2,-1)
But it's not an equation because there is no equal sign and no points are given.
(1,2) (0,5) (-1,8) (2,-1) (-2,11) All of these are solutions to the given equation.
4
(-2, 11)(-3, 14)(2, -1)
-1
There are infinitely many points on any line and it is impossible to list them. The points are those whose x and y coordinates satisfy the given equation.
C. (2, 5) d. (-4, -13)
There are infinitely many points on the line defined by the given equation.
Class point
The equation for the given points is y = x+4 in slope intercept form
If you mean points of (0, 0) and (1, 7) then the equation works out as y = 7x