The slope of a line containing two points (x1, y1) and (x2, y2) is given by:
Slope = m = (y2 - y1)/(x2 - x1).
So, we have these two points as (x1, y1) = (2, 4) and (x2, y2) = (4, 5).
Let's find the slope m:
m = (5 - 4)/(4 - 2) = 1/2.
Since m > 0, then the line rises from left to right. The equation of the line is:
(y - y1) = m(x - x1) This is the point slope form of a linear equation, let's use the first point:
(y - 4) = (1/2)(x - 2)
y - 4 = (1/2)x - 1
y = (1/2)x + 3 This is the slope-intercept form of a linear equation, y = mx + b
The general form of a linear equation is Ax + By + C = 0;
y = (1/2)x + 3
(1/2)x -y + 3 = 0
Points: (2, 6) and (-3, -4) Slope: 2
Slope = (change in Y) / (change in X) = (12 - 9) / (2 - 1) = 3 / 1 = 3
Points: (-2, 5) and (2, -3) Slope: -2
Answer this question… What is the slope of the line that contains the points (-1, 2) and (4, 3)?
Points: (-1, -1) and (-3, 2) Slope: -3/2
The Slope of a line containing the points (2,2) and (4,2) is Y=0
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
Points: (2, 6) and (-3, -4) Slope: 2
Points: (2, 6) and (-3, -4) Slope: 2
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
Zero
If you mean points of (3, 4) and (-6, 10) then the slope is -2/3
Points: (2, 7) and (4, 4) Slope: -3/2
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
The slope of a line that has the points 3, (-4), and has a slope of 2 is 2.
The line contains the points (3,6) and (-2,0). The slope of a line is equal to (y2-y1)/(x2-x1). In this case, the slope is (0-6)/(-2-3), which is (-6)/(-5), which is 6/5 or 1.2.