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When one of the numbers is 0, you must count it to the numbers of data. For example,

1, 0, 3, and 8. To find the average, or the mean, add the four numbers together and divide their sum by 4.

(1 + 0 + 3 + 8)/4= 12/4 = 3

The average is 3.

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Q: How do you calculate an average if one of the numbers is 0?
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How do you write macro programs to calculate average of n numbers?

#include<stdio.h> #define size 100 int main(){ int x[size], sum=0; float average; for(int i=0;i<size;i++){ scanf("%d",x[i]); sum+=x[i]; } average=sum/size; printf("The Average is :\t%d",average); return 0; }


What are 5 numbers that have an average of 0?

3.14159, -2985, 123.456, 2345.89041 and 512.512There are in fact an infinite number of combinations of five numbers that average 0. As long as their sum is 0, like the ones listed above, then their average will be 0 as well.


How do you calculate mean average deviation?

The mean average deviation is the same as the mean deviation (or the average deviation) and they are, by definition, 0.


What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the end points of negative 20 0 and 20 0?

calculate the average of the x-coordinates count by hand take the average of the endpoints *apex*


If the product of two numbers is 0 does one of the numbers have to be 0?

Yes. If a x b = 0 then either a = 0, b = 0, or a = b = 0.


What is the pseudo code for a module to calculate the mean of a 5?

Not sure what you mean by "a 5". To calculate the mean (average) of several numbers, you need to add them all up, then divide by the size of the set. Something like this: counter = 0 sum = 0 for each number in the set { counter++ sum += the individual number } result = sum / counter


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The average deviation of any set of numbers is always 0.


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What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the endpoints of -12 0 and 12 0?

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