After collecting like terms, (3 - 5x - 5 - 12x) reduces to (-2 - 17x).
12x^3+17x^2+5x=0x(12x^2+17x+5)=0x(x+1)(12x+5)=0x=0x=-1x=-5/12
3x-8+5x+39+4x+51 = x(3+5+4) + -8 + 39 + 51 = 12x +82
Simply take the first equation and substitute it for y in the second one. We're told: y = -3x + 5 and: 5x - 4y = -3 So we can say: 5x - 4(-3x + 5) = -3 5x + 12x - 20 = -3 17x = 17 x = 1 Then plug that value into one of our original equations to solve for y: y = -3x + 5 y = -3(1) + 5 y = 5 - 3 y = 2 So the two equations intersect at the point (1, 2).
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
After collecting like terms, (3 - 5x - 5 - 12x) reduces to (-2 - 17x).
12x^3+17x^2+5x=0x(12x^2+17x+5)=0x(x+1)(12x+5)=0x=0x=-1x=-5/12
Think of this a 12 x-rays + 5 x-rays Makes 17 x-rays. 12x+5x=17x
Work it out. 5x+3y=3 3y=-5x+3 y=-5/3x+1 -5/3=the slope in this equation -12x+20y=0 20y=12x y=12/20x y=3/5x 3/5=the slope in this equation If the slopes equal each other, the lines are parallel. If they are the negative reciprocal (the fraction flipped upside down and multiplied by -1) of each other, they are perpendicular. I can't believe I just helped someone this lazy.
This uses the distributive property.
(3x - 2)(5x + 6)
3x-8+5x+39+4x+51 = x(3+5+4) + -8 + 39 + 51 = 12x +82
When x = 5, 12x = 12*5 = 60.
By parenthesis, exponents, multiplication, division,addition and subtraction its 9. And just so you know I'm 11
5x + 10 = 5(x+2) 6x2 + 12x = 6x(x+2) The only common factor is x+2
It is: 6(2x-5) when factored
If I am understanding the problem, "x" is a variable and not multiplication. If this is the problem: -7 <= 5x - 3, then the solution would be as follows: add 3 to both sides of inequlity -7 + 3 <= 5x - 3 + 3 -4 <= 5x divide both sides by 5 -4/5 <= 5x/5 -4/5 <= x or x >= -4/5 or x >= -0.8