5x + 10 = 5(x+2)
6x2 + 12x = 6x(x+2)
The only common factor is x+2
3x(x2 + 2x - 4)
2x(3x+6) = 0 x = 0 or x = -2
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
9+6x2=21
6x2=12 2x-28=?
6x2 - 12x [take out what both terms have in common] 6x(x - 2) [if you multiply 6x by both terms in the parenthesis you will get your original answer]
2(3x^2 + 6x + 2)
3x(x2 + 2x - 4)
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
2x(3x+6) = 0 x = 0 or x = -2
The expression may be : 6x2 + 17x + 12 This factors as, 6x2 + 17x + 12 = (3x + 4)(2x + 3) Or, the expression could be : 6x2 - 17x + 12 This factors as, 6x2 - 17x + 12 = (3x - 4)(2x - 3)
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
To find the least common multiple (LCM) of 6x^2 and 12x, we first need to break down each term into its prime factors. 6x^2 can be broken down into 2 * 3 * x * x, while 12x can be broken down into 2 * 2 * 3 * x. The LCM is the product of all the unique prime factors with the highest power they appear in any of the numbers, which in this case is 2 * 2 * 3 * x * x. Therefore, the LCM of 6x^2 and 12x is 12x^2.
9+6x2=21
Positive
y = -6x2 - 12x - 1We recognize this as the equation of a parabola opening downward, but we don't need to know that in order to answer the question.At the extremes of a function (local max or min), the first derivative of the function = zero.The first derivative of the given function with respect to 'x' is dy/dx = -12x -12Set -12x - 12 = 0.-x - 1 = 0x = -1y = -6x2 - 12x - 1 = -6(1) - 12(-1) - 1 = -6 + 12 - 1 = 5