-a^2- 9a - 18 = 0
-(a^2 + 9a + 18) = 0
-(a + 6)(a + 3) = 0
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If that's 6x2, the answer is (2x + 1)(3x - 2)
(x - 4)(x^2 + 4x + 16)
It can not be factored because its discriminant is less than zero
Let the number be 'm' & 'n'. Hence mn = 54 m + n = 0 It follows m = 0 - n Substitute 0 - n + n = 0 n - n = 0 Hence there are no two numbers that satisfy this system.
x3=x2 x3-x2=0 Factor out x2 x2(x - 1) = 0 If x2=0 then x=0. If x - 1 = 0 then x = 1. Therefore the number is 0 or 1.