If that's 6x2, the answer is (2x + 1)(3x - 2)
(x - 4)(x^2 + 4x + 16)
It can not be factored because its discriminant is less than zero
Let the number be 'm' & 'n'. Hence mn = 54 m + n = 0 It follows m = 0 - n Substitute 0 - n + n = 0 n - n = 0 Hence there are no two numbers that satisfy this system.
x3=x2 x3-x2=0 Factor out x2 x2(x - 1) = 0 If x2=0 then x=0. If x - 1 = 0 then x = 1. Therefore the number is 0 or 1.
Yes.
a(-14-a) = 0 so a = 0 or a = -14
100x2-81
4(x + 1) = 0.
D is the choice that is not true.
Zero Product Property
2(m - 25)
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
(n + 4)(n - 4)
(x + 6)(x - 6)
No, there cannot be a zero in any scale factor.