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x^(2) + 7x + 10

(x + 5)(x + 2)

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lenpollock

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2w ago

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Related Questions

How do you factor x2-7x plus 10?

(x - 5)(x - 2)


What is the factor of x2 plus 7x-30?

(x + 10)(x - 3)


How do you factor x2 plus 7x plus 6?

x2 + 7x + 6 = (x + 6) (x + 1)


X2 plus 7x plus 10 equals?

The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth


Factor x2 plus 7x plus 12?

=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).


What is the factor of the polynomial in descending order x2 plus 7x plus 10?

Restate the question: Factor the polynomial x2 + 7x + 10. You look for two numbers which multiply to make 10 and add to make 7. They are 5 and 2. Now put them into the two factors: (x + 5)(x + 2). Check your factors by multiplying using 'FOIL': x2 + 2x + 5x + 10 = x2 + 7x + 10. Check!


Is it possible to factor x2 plus 7x minus 144?

Easy, peasy! x2 + 7x - 144 = (x + 16)(x - 9).


How do you solve x2 plus 7x plus 12?

You cannot solve, without equating it to something. As given it is just an expression. However it can be factored. x^(2) + 7x +12 ( x + 3)(x + 4) Factored but NOT solved. However, it we equate to 'zero(0)' then it can be solved. ( x + 3)( x + 4) = 0 X + 3 = 0 x = -3 Similarly x + 4 = 0 x = -4 Are the solutions (solved).


How do you factor x2 plus 7x plus 10?

Find two numbers that add up to make 7 (the coefficient of the second term) and which multiply to make 10 (the product of the coefficients of the first and last terms - 1*10): x2 + 7x + 10 = x2 + 5x + 2x + 10 = x(x + 5) + 2(x + 5) = (x + 2)(x + 5)


What is the factor to x squared plus 7x minus 18?

(x2 + 7x - 18) = (x + 9)(x - 2)


What is the factor of x2 plus 7x plus 12 equals 0?

(x + 3)(x + 4)


How do you factor x2-y2 plus 7x plus 7y?

(x - y + 7)(x + y)