Easy, peasy! x2 + 7x - 144 = (x + 16)(x - 9).
x2+7x+12
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
-3
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
(x - 5)(x - 2)
(x + 10)(x - 3)
x2 + 7x + 6 = (x + 6) (x + 1)
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).
Restate the question: Factor the polynomial x2 + 7x + 10. You look for two numbers which multiply to make 10 and add to make 7. They are 5 and 2. Now put them into the two factors: (x + 5)(x + 2). Check your factors by multiplying using 'FOIL': x2 + 2x + 5x + 10 = x2 + 7x + 10. Check!
Easy, peasy! x2 + 7x - 144 = (x + 16)(x - 9).
x2+7x+12
Find two numbers that add up to make 7 (the coefficient of the second term) and which multiply to make 10 (the product of the coefficients of the first and last terms - 1*10): x2 + 7x + 10 = x2 + 5x + 2x + 10 = x(x + 5) + 2(x + 5) = (x + 2)(x + 5)
(x2 + 7x - 18) = (x + 9)(x - 2)
(x + 3)(x + 4)
(x - y + 7)(x + y)