-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
5
3r-2 for r=65
2
Triple r in an algebraic expression simply means multiplying the variable r by 3. So if you see "3r" in an expression, it's the same as saying "triple r." It's like saying "three times the fun with r" in math language.
If that's 3r + 12, that factors to 3(r + 4)
(3r + 2)(r - 5)
factor out the common monomial, 5. 5(r^3-1) Factor as a difference of cubes. 5(r-1)(r^2+r+1)
(3r - 2)(3r - 2) or (3r - 2) squared.
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
7 + r(3 - t)
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
If: -5 = 7+3r then the value of r works out as -4
To factor the expression 4q^2 - 27r^4, we first note that this is a difference of squares, as 4q^2 is (2q)^2 and 27r^4 is (3r^2)^3. Therefore, we can rewrite the expression as (2q)^2 - (3r^2)^2. This can be factored further using the difference of squares formula, resulting in (2q + 3r^2)(2q - 3r^2) as the completely factored form.
3r-r equals 12 = -9
5
3r/4