-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
5
3r-2 for r=65
In algebra, "r" typically represents a variable or an unknown quantity. When you see "triple r" in an algebraic expression, it means that you are multiplying the variable "r" by three. So, "triple r" is equivalent to 3r in algebraic terms. This can be written as 3 * r or simply 3r, depending on the context of the expression.
2
If that's 3r + 12, that factors to 3(r + 4)
(3r + 2)(r - 5)
factor out the common monomial, 5. 5(r^3-1) Factor as a difference of cubes. 5(r-1)(r^2+r+1)
(3r - 2)(3r - 2) or (3r - 2) squared.
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
7 + r(3 - t)
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
If: -5 = 7+3r then the value of r works out as -4
To factor the expression 4q^2 - 27r^4, we first note that this is a difference of squares, as 4q^2 is (2q)^2 and 27r^4 is (3r^2)^3. Therefore, we can rewrite the expression as (2q)^2 - (3r^2)^2. This can be factored further using the difference of squares formula, resulting in (2q + 3r^2)(2q - 3r^2) as the completely factored form.
3r-r equals 12 = -9
5
3r/4