Let the numbers be 'm' & 'n'
Hence
mn = 51 (Multiplication)
m + n = -16 (Addition)
Algebraically rearrange
m = -16 -n
Ssubstitute
(-16-n) n = 51
-16n - n^2 = 51
n^(2) + 16n + 51 = 0 ( It is now in Quadratic form to solve).
Complete the Square
(n + 8)^2 - 8^(2) = -51
(n + 8)^2 = -51 + 64 = 13
Square root both sides
n + 8 = +/-sqrt(13)
n + 8 = +/- 3.60555....
n = -13.60555.... & -4.39444.... Are the two number.
number to add to 51 to equal 180 = 129180 - 51 = 129
Let's say you want to multiply something by 51%. You multiply 51 by 0.01, which gives you 0.51. So you're equation would be: (NUMBER) x 0.51.
1/3 + 2/17need common denominator to add fractions and with this oddball just multiply 3 * 17 = 51 and use form of one to get fractions into order17*1/17*3 + 3*2/3*1717/51 + 6/51= 23/51=======simplest form
Only 51. (51 = 3 x 17)
{x+y=51, x-y=26} x=38.5 y=12.5
51
-51
51
54
16, 17, and 18
54
1x51=51
-37
-51
17 x 3= 51
Just add the numbers. Then divide the result by "how many numbers are there", in this case, 6.
The prime factors of 51 are 3 and 17.