Let the numbers be 'm' & 'n'
Hence
mn = 51 (Multiplication)
m + n = -16 (Addition)
Algebraically rearrange
m = -16 -n
Ssubstitute
(-16-n) n = 51
-16n - n^2 = 51
n^(2) + 16n + 51 = 0 ( It is now in Quadratic form to solve).
Complete the Square
(n + 8)^2 - 8^(2) = -51
(n + 8)^2 = -51 + 64 = 13
Square root both sides
n + 8 = +/-sqrt(13)
n + 8 = +/- 3.60555....
n = -13.60555.... & -4.39444.... Are the two number.
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The factor pairs of 51 are (51,1)(17,3)
Even if you count their negative counterparts, none of them will add up to -16.
Let's say you want to multiply something by 51%. You multiply 51 by 0.01, which gives you 0.51. So you're equation would be: (NUMBER) x 0.51.
1/3 + 2/17need common denominator to add fractions and with this oddball just multiply 3 * 17 = 51 and use form of one to get fractions into order17*1/17*3 + 3*2/3*1717/51 + 6/51= 23/51=======simplest form
To find what can be added to 51 to equal 180, you would subtract 51 from 180. This would give you 129. Therefore, 129 can be added to 51 to equal 180.
Only 51. (51 = 3 x 17)
{x+y=51, x-y=26} x=38.5 y=12.5