I assume you mean 5x2+5x-10 in my answer:
When factoring ax2+bx+c, find two numbers which multiply to give a*c and add to give b.
In this case, a*c = -50 and b = 5
So the two numbers are 10 and -5.
Now, rewrite the middle term with these two coefficients:
5x2 + 10x - 5x - 10 (Notice it's the same expression because 10x - 5x = 5x as in the original)
We can factor the first half: 5x2 + 10x as 5x(x + 2)
Then, we factor the second half: -5x - 10 (don't forget the signs in front) as -5(x + 2)
We rewrite the original now as 5x(x+2) - 5(x+2)
But then we have (x+2) as a factor of both term, so we take it out the front:
(x+2)(5x - 5) and this is the factored form.
You could proceed further to 5(x+2)(x-1) if required by extracting the 5 from the second term.
5x2
(5x-6)(x-3)
(5x - 1)(x + 6)
To factor any term, divide by the LCF (largest common factor) of the term. For 5x2-45, the LCF is 5. 5x2-45 = 5(x2-9) It can, of course, be factored even further to become: 5(x2-9) = 45(x2/9 - 1) but when factoring, we usually don't need to go past 5(x2-9) (for example, you've figured out that x2 = 9, thus x = +/- 3.)
False
60
5x2 + 3x - 1 does not have rational factors.
1x50 2x25 5x10
5x2-46x+9 = (5x-1)(x-9)
5x2 + 20x = 5x (x + 4)
5x2-18x+9 = (5x-3)(x-3)
x(5x - 4)
With great difficulty!
5x2
5x2 + x - 6 = (5x + 6)(x - 1) 5x2 - x - 6 = (5x - 6)(x + 1)
The GCF is 5x2
5x2