(x+2)(x+1) = x^2 + 1x + 2x + 2 = x^2 + 3x +2
If you mean: x2+3x+2 then it is (x+1)(x+2) when factored
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
x2 + 3x - 40 = (x + 8)(x - 5)
x2 - 3X - 10 = (X - 5)(X + 2)So, (X2 - 3X -10) / (X-5) = X + 2
x2 + 3x + 28 can not be factored. If on the other hand you meant to type: x2 + 3x - 28 That can indeed be factored: = x2 + 7x - 4x - 28 = x(x + 7) - 4(x + 7) = (x - 4)(x + 7)
If you mean: x2+3x+2 then it is (x+1)(x+2) when factored
x2-3x-28
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
x2-3x-10 = (x+2)(x-5) when factored
(x - 1)(x - 2)
-1
(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2 (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3 (x + 1) is a common monomial factor of the polynomials x2 + 3x + 2 and x2 + 4x + 3
If you mean: x^2 +3x -10 then when factored it is (x-2)(x+5)
x2 + 3x - 40 = (x + 8)(x - 5)
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3