x2-3x-10 = (x+2)(x-5) when factored
(x2 + 3x + 5)(x2 - 3x + 4)
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
For any x ≠ 0, x2 -10/x2 - 4 +3x/x2 - 4 LCD = x2, multiply each term by their missing element of LCD = (x4 + 10 +3x - 8x2)/x = (x4 - 8x2 + 3x + 10)/x2
x2 - 3x - 40 = (x - 8) (x + 5)
x2-3x-28
13
It factors to: (x-4)(x+1)
If you mean: x^2 +3x -10 then when factored it is (x-2)(x+5)
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
x2 + 3x - 40 = (x + 8)(x - 5)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)