x3 + 3x2 - 4x -12
x2(x + 3) - 4(x + 3)
(x2 - 4)(x+3)
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x2(x3 + 1) is the best you can do there.
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7