Oh, what a happy little equation we have here! To factor x cubed minus x, we first notice that both terms have x in common. So, we can factor out an x to get x(x squared - 1). Then, we see that x squared minus 1 is a difference of squares, so we can further factor it to get x(x + 1)(x - 1). And just like that, we've created a beautiful factored expression!
Oh, dude, it's like you want to factor x cubed minus x? Easy peasy lemon squeezy! Just pull out an x from each term, because x is like the common factor, and you're left with x(x squared - 1). Then, you can factor x squared - 1 into (x + 1)(x - 1). Voilà! You've factored x cubed minus x like a boss.
Factor out the GCF and get X(X2-X+1).
(x - 1)(x^2 + x + 1)
(x - 4)(x^2 + 4x + 16)
24
x^3 - x^3 = 0 Remember , whilst 'x' is an unknown value, that unkonwn is a fixed value. As a numerical example 3^(3) - 3^(3) = 27 - 27 = 0 The '3' is 'x' in this case
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
x(x + 3)(x - 4)
x cubed minus 216
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
Factor out the GCF and get X(X2-X+1).
x(x + 1)(x -1)
(x - 1)(x^2 + x + 1)
(x - 2)(x^2 + x + 3)
t3-1/27
There are no factors with rational coefficients.
2(5x - 6y)(25x2 + 30xy + 36y2)
(x - 5)(x^2 + 1)