4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
-4x2 + 5x + 6 = 0 Multiply through by -1: 4x2 - 5x - 6 = 0 (I prefer the leading coefficient to be >0) 4x2 - 8x + 3x - 6 = 0 4x(x - 2) + 3(x - 2) = 0 (x - 2)(4x + 3) = 0 So x - 2 = 0 or 4x + 3 = 0 ie x = 2 or x = -3/4
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
Divide all terms by 4:- x2+5x-6 = (x-1)(x+6) when factored
x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
(4x-3)(x+2)
-4x2 + 5x + 6 = 0 Multiply through by -1: 4x2 - 5x - 6 = 0 (I prefer the leading coefficient to be >0) 4x2 - 8x + 3x - 6 = 0 4x(x - 2) + 3(x - 2) = 0 (x - 2)(4x + 3) = 0 So x - 2 = 0 or 4x + 3 = 0 ie x = 2 or x = -3/4
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
3x2 - 5x - 22 (x + 2)(3x - 11) x = -2, 11/3 Neither is a multiple of 6.
3y = 5xy = x + 23y = 5x3(x + 2) = 5x3x + 6 = 5x3x - 3x + 6 = 5x - 3x6 = 2x6/2 = 2x/23 = xy = x + 2 = 3 + 2 = 5Thus, the solution of the set is (3, 5)Check:
5x^2 + 6x - 2 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-3 plus or minus the square root of 19) divided by 5. x = 0.2717797887081348 x = -1.4717797887081348
Divide all terms by 4:- x2+5x-6 = (x-1)(x+6) when factored
x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)
yes. check: 3x-6=5x-10 2x=4. X=2. yay!
If you mean: x2+5x+6 = 0 then the solutions are x = -3 and x = -2