x2+6x-7 = (x+7)(x-1) when factored
Rearrange the quadratic equation to: x2-6x-9 = 0 and use the quadratic equation formula to find the values of x which are:- x = -1.2426406871 or x = 7.2426406871 When factored: (x+1.2426406871)(x-7.242406871) = 0
With great difficulty not knowing if 6x and 27 are plus or minus
(x + 3)(4x + 5)
-x(x2 - 2)(x2 + 3)
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
5x2-2x+16=4x2+6x ,or x2-8x+16=0, or x2-2(x)(4)+(4)2=0, or (x-4)2=0, or (x-4)(x-4)=0, or x=4
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
4(x2 - 6x + 13)
4x2 + x2 = 8 + x2
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
one
(3, -21)
y ≥ 11
x2 + 6x - 2 = 0 x2 + 6x + 9 = 13 (x + 3)2 = 13 x + 3 = ± √13 x = -3 ± √13