Factorise fully is when brackets are involved in the equation
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
Without an equality sign the given terms can't be considered to be an equation.
Without an equality sign the given terms can't considered to be an equation and so therefore it has no solution.
You can evaluate a polynomial, you can factorise a polynomial, you can solve a polynomial equation. But a polynomial is not a specific question so it cannot be answered.
Factorise fully is when brackets are involved in the equation
Factorise it!
X(X2 - X)
Presumably this is a quadratic equation in the form of -8k2-12+92 = 0 which will have two solutions. First divide all terms by -4 to bring the equation at its lowest terms remembering that a - divided into a - is equal to a + 2k2+3k-23 = 0 Use the quadratic equation formula to factorise the equation: (2k-5.446221994)(k+4.223110997) = 0 Therefore the solutions are: k = 2.723110997 or k = -4.223110997 to nine decimal places respectively.
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
If you mean the quadratic expression: 2x2+8x+6 then dividing all terms by 2 it becomes x2+4x+3 which is (x+1)(x+3) when factored
With the help of the quadratic equation formula
4(x2 + 4)
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
4
2(3n+4)