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The easiest way is to use synthetic division. This cannot be sensibly explained without images. More information here: wikipedia.org/wiki/Synthetic_division

The factors can be found by trial and error.

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Q: How do you factorise an equation with 4 terms?
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Related questions

What does factorise fully mean?

Factorise fully is when brackets are involved in the equation


How do you know if a quadratic equation will have whether or not it will have solutions?

Factorise it!


How do you solve the equation Factorise x3 4x?

X(X2 - X)


Solve -8k2 -12k plus 92?

Presumably this is a quadratic equation in the form of -8k2-12+92 = 0 which will have two solutions. First divide all terms by -4 to bring the equation at its lowest terms remembering that a - divided into a - is equal to a + 2k2+3k-23 = 0 Use the quadratic equation formula to factorise the equation: (2k-5.446221994)(k+4.223110997) = 0 Therefore the solutions are: k = 2.723110997 or k = -4.223110997 to nine decimal places respectively.


How do you factorise a question that already has brackets?

The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.


What would you do if the equation had x squared or x cubed in the polynomial equation?

It depends on what you wanted to do - graph it, solve it, factorise it, etc.


Is it good to divide the equation 2x squared 8x 6 by two to factorise such equation?

If you mean the quadratic expression: 2x2+8x+6 then dividing all terms by 2 it becomes x2+4x+3 which is (x+1)(x+3) when factored


How do you factorise 12x squared minus 9x minus 14?

With the help of the quadratic equation formula


How do you factorise 4x2 plus 16?

4(x2 + 4)


X2 - 6x equals -8?

This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4


What is 2x -2?

4


What is the answer to this equation 7-4 3x0 1?

Without an equality sign the given terms can't be considered to be an equation.