x^2 - 5x - 6
Since the coefficient of 'x^(2)' is '1' in this case. we look at the constant '6' .
So write down all the factors of 6' . They are 1,2,3,&6.
From these four number we select two numbers that add/subtract to '-
So if we say -6 + 1 = -5 5'. The coefficient of 'x'
Since 6 - 1 = 5 & 2 + 3 = 5 We need to think a little deeper. So we look at the mathemetical signs , which in this case are both negative (-).
Since the sign in front of the '6' is negative, this means that the signs in the brackets are different. NB If it was a possitive both the signs in brackets would be the same either both (+) or both (-).
So to have a '-5' we can say -6 + 1 = -5
So setting up the brackets
( x 6 )(x 1) So the signs will be
(x - 6)( x + 1)
Done!!!! Hope that helps!!!!
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(5x + 2)(x + 3)
(4x-3)(x+2)
It is (x+6)(x+7) when factored
It is: x(x-3) factorized
The solutions to the quadratic equation are: x = -1 and x = 6