First you half all the sides, so 4cm, them you multiply by pi, giving the radius as 12pi, or 12.56637061
Pythagoras! Two sides of the triangle must each be equal to the radius, ie 3 so Hypotenuse = sqrt(3^2 + 3^2) =sqrt 18 = 4.243
Depends on what shape you're looking to find the area of.Area of a rectangle = Length x Width x Height(same for parallelogram)Area of a triangle = 1/2 Base x Height or S^2 times root four divided by threeCircumference of a circle = 22/7 (of 3.14) x the diameter of the circle. A Square or Rectangle: Multiply the length of the rectangle by the width of the rectangle or the opposite. A Triangle: Multiply the the Base length (from the bottom of triangle to the tip on top) by the Width of the triangle. Then, divide your results in half. A Circle: Multiply the radius by radius by 3.14 (pi) to find answer.
radius = diameter/2
radius = circumference/(2*pi)
A radius of a regular triangle is 12 . find the length of one side of the triangle?
you have a triangle formed by the radius on 2 and the chord on the other. the angle in that triangle that is opposite the chord, find its measure in radians take that measure (in radians) and multiply it by the radius to get the arc length
the formula for the arc of a triangle is the arc length is equal to the angle times the radius. s=arc length theta=angle made y length of the arc lenth r=radius s=theta times radius
First you half all the sides, so 4cm, them you multiply by pi, giving the radius as 12pi, or 12.56637061
Double its radius
What do you mean by the radius of 4? Radius is used in circles. Do you mean that the breadth is 4? If so you can use Pythagoras's Theorem to find the 'slant height' (provided that it is a right-angle triangle) (slant height)2=52+42
a/root3
Uisng the lateral area and tha radius, you should be able to find the height of the cone. Using the height and radius as the legs of a right triangle, use the Pythagorean Theorem. The hypotenuse is the slant height.
Write a program that calculates the area of a triangle in QBASIC
Make a sketch of the situation. From a corner of the equilateral triangle draw a radius of the large circle, and from an adjacent side draw a radius of the smaller circle. You should have formed a small right-angled triangle with a known side of 10cm. and known angles of 30o, 60o and 90o. (The interior angles of an equilateral triangle are each 60o.) The hypotenuse is the unknown radius of the larger circle. But since cos 60 = 0.5, it is evident that the hypotenuse is 20cm. long.
The diameter of the circle will also be the triangle's hypotenuse so use Pythagoras theorem to find the hypotenuse's length and half the length which will result as a radius of 5 cm.
These are some characteristics of equilateral triangle:All the sides of an equilateral triangle are equalIn an equilateral triangle each angle is angle is 60 degree.With an equilateral triangle, the radius of the incircle is exactly half the radius of the circumcircle.