Take the derivative of the function.
it depends on what b is in the equation. Period = 360 degrees / absolute value of b.
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
The first thing you may want to do would be to find the tangent line to the function. The tangent line is a line that passes through a given point on a function, but does not touch any other point on the function (assuming the function is one to one). Assuming you have the tangent line, the normal line is simply perpendicular to the tangent line- it forms a 90 degree angle with the tangent line. One you have the tangent line and the point which it passes through, you can find the normal line. To obtain the perpendicular line to any function, take the inverse reciprocal of the slope (if your slope was 2, it is now -.5). After that, plug in your (x, y) coordinate, and you can solve for the constant b (assuming there is one). This should give the normal line to a tangent of at a point on a function.
The period of the tangent function, tan(x), is π because the tangent function has a repeating pattern every π units. This is due to the nature of the tangent function, which has vertical asymptotes at intervals of π. As x increases by π, the tangent function repeats its values, resulting in a period of π for the function.
Take the derivative of the function.
it depends on what b is in the equation. Period = 360 degrees / absolute value of b.
The graph of the tangent function is periodic at every point. Periodic means that the value of the function at every point is repeated after an integer multiple of the period.
The tangent function is a periodic function with period 180 degrees sotan(360) = tan(360-2*180) = tan(0) = 0.
Yes, the tangent function is periodic.
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
To find the tangent of 1, you can use the inverse tangent function (arctan) on a calculator. Simply input 1 into the arctan function and calculate the result. The tangent of 1 is approximately 0.7854.
A tangent line is NEVER vertical to a function. It is vertical to the normal to the function - which is as far from vertical as you can get!The graph of a function, f(x) can have a tangent at a point. Let's call the point (x0,f(x0)). If f'(x) goes to positive infinity or f'(x) goes to negative infinity as x approaches x0 then f(x) has a vertical tangent at that point.
The first thing you may want to do would be to find the tangent line to the function. The tangent line is a line that passes through a given point on a function, but does not touch any other point on the function (assuming the function is one to one). Assuming you have the tangent line, the normal line is simply perpendicular to the tangent line- it forms a 90 degree angle with the tangent line. One you have the tangent line and the point which it passes through, you can find the normal line. To obtain the perpendicular line to any function, take the inverse reciprocal of the slope (if your slope was 2, it is now -.5). After that, plug in your (x, y) coordinate, and you can solve for the constant b (assuming there is one). This should give the normal line to a tangent of at a point on a function.
No.
The period of the tangent function, tan(x), is π because the tangent function has a repeating pattern every π units. This is due to the nature of the tangent function, which has vertical asymptotes at intervals of π. As x increases by π, the tangent function repeats its values, resulting in a period of π for the function.