For a line, this is the x-intercept. For a polynomial, these points are the roots or solutions of the polynomial at which y=0.
No. An expression can have a variable exponent (for instance, 2 to the power x, or x to the power y), but that is no longer a polynomial.
if you make a t chart with the x and y, you can find functions. the change in y is the number in front of the x (multiplying) and if you find the x at 0, the y will be what you add. here: y=3x + 1 the 3 is the change in y the + 1 when you have (0, 1) as a point. subistite the axis of symmetry into the original problem and solve for y. inentify the vertex
You can factor this multivariate polynomial (a polynomial with several variables, here x and y), by looking at it as a univariate polynomial in either x or y. This would give you a simple second order equation of the form ax2+bx+c, which you can solve. This will give you 2 solutions, say x1 and x2, and can then factor your polynomial to a(x-x1)(x-x2). In our case: a=8, b=-y and c=-7y2 and the solutions for this equation are x1=y and x2=-7/8*y and this gives us 8x2 - xy -7y2 = 8(x-y)(x+7/8y) = (x-y)(8x+7y)
The question cannot be answered without information about the nature of the curve, for example, what degree polynomial (if it is a polynomial).
Yes. A lot of hyperbolic functions have no y- intercept. Also functions of the form Y=1/x^n Will only go to positive infinity as it approaches zero from the positive x direction and go to negative infinity as it approaches zero from the negative x direction. * * * * * While all that is true, the functions mentioned in the above answer are not polynomial functions! All polynomial functions will have a y-intercept provided there is no additional restriction on the domain so as to exclude x = 0.
It is a polynomial in x and y.
no...
Basically the same way you graph most functions. You can calculate pairs of value - you express the polynomial as y = p(x), that is, the y-values are calculated on the basis of the x-values, you assign different values for "x", and calculate the corresponding values for "y". Then graph them. You can get more information about a polynomial if you know calculus. Calculus books sometimes have a chapter on graphing equations. For example: if you calculate the derivative of a polynomial and then calculate when this derivate is equal to zero, you will find the points at which the polynomial may have maximum or minimum values, and if you calculate the derivative at any point, you'll see whether the polynomial increases or decreases at that point (from left to right), depending on whether the derivative is positive or negative. Also, if you calculate when the second derivative is equal to zero, you'll find points at which the polynomial may change from convex to concave or vice-versa.
Basically the same way you graph most functions. You can calculate pairs of value - you express the polynomial as y = p(x), that is, the y-values are calculated on the basis of the x-values, you assign different values for "x", and calculate the corresponding values for "y". Then graph them. You can get more information about a polynomial if you know calculus. Calculus books sometimes have a chapter on graphing equations. For example: if you calculate the derivative of a polynomial and then calculate when this derivate is equal to zero, you will find the points at which the polynomial may have maximum or minimum values, and if you calculate the derivative at any point, you'll see whether the polynomial increases or decreases at that point (from left to right), depending on whether the derivative is positive or negative. Also, if you calculate when the second derivative is equal to zero, you'll find points at which the polynomial may change from convex to concave or vice-versa.
For a polynomial of the form y = p(x) (i.e., some polynomial function of x), having a y-intercept simply means that the polynomial is defined for x = 0 - and a polynomial is defined for any value of "x". As for the x-intercept: from left to right, a polynomial of even degree may come down, not quite reach zero, and then go back up again. A simple example is y = x2 + 1. Why is the situation for "x" and for "y" different? Well, the original equation is a polynomial in "x"; but if you solve for "x", you don't get a polynomial in "y".
Either graph the polynomial on graph paper manually or on a graphing calculator. If it is a "y=" polynomial, then the zeroes are the points or point where the polynomial touches the x-axis. If it is an "x=" polynomial, then the zeroes are the points or point where the polynomial touches the y-axis. If it touches neither, then it has no zeroes.
Yes. think of a parabola that curves around the y-axis. an equation like x = square root of (y2 - 9) simply switch the x's and y's in the equation and your parabola opens up around the y-axis and the x-axis respectively
A polynomial with a degree of one, of the form y = ax + b, where a and b are constants.
It is a polynomial of degree one in x, and also a polynomial of degree one in y.
Not quite. The polynomial's linear factors are related - not equal to - the places where the graph meets the x-axis. For example, the polynomial x2 - 5x + 6, in factored form, is (x - 2) (x - 3). In this case, +2 and +3 are "zeroes" of the polynomial, i.e., the graph crosses the x-axis. That is, in an x-y graph, y = 0.
YES! A polynomial is made up of terms that are only added, subtracted or multiplied. Division is not allowed. It may have constants, exponents or variables. A monomial is one type of polynomial. y+2y is the same as 4y which is a monomial. It has degree 1 since the exponent on y is 1.