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What is the point at which a graph crosses the x-axis?
For a line, this is the x-intercept. For a polynomial, these points are the roots or solutions of the polynomial at which y=0.
Can a polynomial have a variable exponent?
No. An expression can have a variable exponent (for instance, 2 to the power x, or x to the power y), but that is no longer a polynomial.
How do you do functions in math?
if you make a t chart with the x and y, you can find functions. the change in y is the number in front of the x (multiplying) and if you find the x at 0, the y will be what you add. here: y=3x + 1 the 3 is the change in y the + 1 when you have (0, 1) as a point. subistite the axis of symmetry into the original problem and solve for y. inentify the vertex
What is the x intercept of vertex (7-12) and y intercept (0135)?
The question cannot be answered without information about the nature of the curve, for example, what degree polynomial (if it is a polynomial).
How would you factor 8x2 - xy - 7y2 The 2 after the x and y are the squares. so its 8x squared - xy - 7y squared.?
You can factor this multivariate polynomial (a polynomial with several variables, here x and y), by looking at it as a univariate polynomial in either x or y. This would give you a simple second order equation of the form ax2+bx+c, which you can solve. This will give you 2 solutions, say x1 and x2, and can then factor your polynomial to a(x-x1)(x-x2). In our case: a=8, b=-y and c=-7y2 and the solutions for this equation are x1=y and x2=-7/8*y and this gives us 8x2 - xy -7y2 = 8(x-y)(x+7/8y) = (x-y)(8x+7y)
