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How do you get a parabola with only one x intercept?
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
Intercept form for parabola?
Oh honey, the intercept form for a parabola is just a fancy way of saying the equation looks like y = a(x - h)(x - k). The (h, k) represents the coordinates of the vertex, and the 'a' is the same 'a' you see in vertex form - it just tells you if the parabola opens up or down. So there you have it, intercept form in a nutshell. Hope that clears things up for ya!
What is the importance of the x-intercept?
What is the importance of the x-intercept What is the importance of the x-intercept What is the importance of the x-intercept
What is X squared plus six x plus five?
It is the parabolic function defined by the product (x+1)(x+5), with x intercepts at -1 and -5, y-intercept at (0,5) and a vertex at (-3, -4).
What is the difference between the x- intercept and the y- intercept?
The y-intercept is where the line crosses the y-axis, and the x-intercept is where the line cross the x-axis
How do you find the x intercepts using the vertex and y intercept?
It depends on the vertex of what!
What is the vertex of a parabola?
the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)
How do you get a parabola with only one x intercept?
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
Find the x intercept or interceptss and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
-2, 6
How do you graph quadratic functions?
if it's in the form of ax + bx +c , then to graph it you need to find the roots (intercept ) and its vertex and the y-intercept. to find the roots, you factor it, like this: for example, you have this, x + 8x + 15, you factor to this: ( x + 3 ) ( x + 5). those two numbers ( +3 and +5) , you switch the signs so that they are -3 and -5. those are the roots. To find the y-intercept, in the expression, you make the x equal zero, and whatever number you simplify it to is the y-intercept. to find the vertex, you apply the formula x=-b/ 2a. whatever number you end up with is the x coordinate of the vertex. to find the y coordinate, you simply substitute the x value in the expression and simplify it and whatever you end up with is the y coordinate. you plot that coordinate, which is the vertex. it has to be curved. make it touch the y axis at the y intercept and the x axis at the roots. That's it.
Find the x intercept or intercepts and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.
What form of a quadratic function would be graphed having the vertex at the same point as the y- intercept?
The function would be in the form of ax2+c. The axis of symmetry would be the y-axis, or x = 0, because b would be zero. Likewise, the y-intercept is not important, as any value of c will still yield a vertex at the y-intercept.
Intercept form for parabola?
Oh honey, the intercept form for a parabola is just a fancy way of saying the equation looks like y = a(x - h)(x - k). The (h, k) represents the coordinates of the vertex, and the 'a' is the same 'a' you see in vertex form - it just tells you if the parabola opens up or down. So there you have it, intercept form in a nutshell. Hope that clears things up for ya!
What is the importance of the x-intercept?
What is the importance of the x-intercept What is the importance of the x-intercept What is the importance of the x-intercept
What is the prime factorization for 712?
2 x 2 x 2 x 89 = 712
The vertex of this parabola is at 3 -2 When the x value is 4 the y value is 3 What is the coefficient of the squared expression in the parabolas equation?
Vertex = (3, - 2)Put in vertex form.(X - 3)2 + 2X2 - 6X + 9 + 2 = 0X2 - 6X + 11 = 0=============The coefficeint of the squared term is 1. My TI-84 confirms the (4, 3) intercept of the parabola and the 11 Y intercept shown by the function.
What is X squared plus six x plus five?
It is the parabolic function defined by the product (x+1)(x+5), with x intercepts at -1 and -5, y-intercept at (0,5) and a vertex at (-3, -4).
