Let x = 0 (cover up the x term): -3y = -15 so y = 5
Mark the point P = (0, 5) on a coordinate plane.
Let y = 0 (cover up the y term): 10x = -15 so x = -1.5
Mark the point Q = (-1.5, 0) on a coordinate plane.
Join up the points PQ and extend the straight line in both directions.
Let x = 0 (cover up the x term): -3y = -15 so y = 5
Mark the point P = (0, 5) on a coordinate plane.
Let y = 0 (cover up the y term): 10x = -15 so x = -1.5
Mark the point Q = (-1.5, 0) on a coordinate plane.
Join up the points PQ and extend the straight line in both directions.
Let x = 0 (cover up the x term): -3y = -15 so y = 5
Mark the point P = (0, 5) on a coordinate plane.
Let y = 0 (cover up the y term): 10x = -15 so x = -1.5
Mark the point Q = (-1.5, 0) on a coordinate plane.
Join up the points PQ and extend the straight line in both directions.
Let x = 0 (cover up the x term): -3y = -15 so y = 5
Mark the point P = (0, 5) on a coordinate plane.
Let y = 0 (cover up the y term): 10x = -15 so x = -1.5
Mark the point Q = (-1.5, 0) on a coordinate plane.
Join up the points PQ and extend the straight line in both directions.
8
y=x+1 there for answer is 2
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
The picture of the graph is in the related links section.
-5
The slope of the line that represents the graph of that equation is 15.
x intercept = 5 y intercept = 15
No translation will invert a quadratic graph.
35
The highest point on a graph is when the derivative of the graph equals 0 or the slope is constant.
Any graph with the slope of -1/2
X intercept: -5 Y intercept: +3
-2
Yes, that is a shifted tanX graph, just as you would shift any graft.
3
8
There needs to be an x variable to create a graph.