The graph of the function y = (sin x)^2 has the same amplitude 1, and the same period 2pi, as the graph of the function y = sin x. The only difference between them is that the part of the graph of y = sin x which is below the x-axis is reflected above x axis.
In order to graph the function y = (sin x)^2, we need to find the values of (x, y) for the five key points, where 0 ≤ x ≤ 2pi.
Values of (x, y) on y = (sin x)^2:
x = 0, y = 0
x = pi/2, y = 1
x = pi, y = 0
x = 3pi/2, y = 1
x = 2pi, y = 0
Plot these five key points and connect them with a smooth curve and graph one complete cycle of the given function.
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Sin squared, cos squared...you removed the x in the equation.
2 x cosine squared x -1 which also equals cos (2x)
To shift a funcion (or its graph) down "a" units, you subtract "a" from the function. For example, x squared gives you a certain graph; "x squared minus a" will give you the same graph, but shifted down "a" units. Similarly, you can shift a graph upwards "a" units, by adding "a" to the function.
2
sin(x)*sin2(x) = 1 so sin3(x) = 1 so that sin(x) = cuberoot(1) = 1 then x = pi/2 + n*pi where n is an integer.