y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
6
y=x+1 there for answer is 2
You just have to plug in numbers for x and plot it on a graph. You can't have a square root of a negative number, so the graph starts at 0 and moves to the right. You'll have to use a calculator to get the decimal approximation for some of y values. x=0, y=0 x=1, y=1 x=2, y= square root of 2 x=3, y=square root of 3 x=4, y=2 x=5, y=square root of 5 etc...
y = x is a line diagonally from the bottom left to bottom right. e.g plot the points (-1,-1) , (0,0) , (1,1) then hook them up and continue the line
if this is an x,y plot, it would be a vertical line at x = -3
3,1 4,2 5,3 Ect
its easier solve for y an plot the corresponding pointsyou,ll get Y=-x+9 an then you find your coordinate points-2,11-1,100,91,82,73,6etcand then plot those points
First note that this not the graph of y = |cot(x)|.The equivalent equations for |y| = cot(x) or cot(x) = |y| arecot(x) = -y or cot(x) = +ySo plot y = cot x and then reflect all the points in the x-axis.
y=x+4 To graph this, you need to find the y-intercept in the equation which is 4. Plot that on the graph by going up 4 from the origin (0,0). Next, go right one, up one and plot. Then, right one, up one again.
X = 4 is a vertical line, 4 units to the right of the y-axis.
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
6
y=x+1 there for answer is 2
The graph is a horizontal line at y=3
Select a set of values of x for which you wish to plot the graph - a subset of the domain. For each value x, calculate y = negative x to the second power = -x2. Plot the set of ordered points (x, y) = (x, -x2) on a coordinate plane and jion them together with a smooth curve.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.