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How do you graph a line using slope intercept form of a linear equation?
you create ordered pairs or a serious of (x,y) points on the graph which you can plot and connect with a straight line
How do you solve this simultaneous equation 2y equals 12-x and 3y equals x-2 by using a graph?
Plot the straight line representing 2y = 12 - x. Plot the straight line representing 3y = x - 2 The coordinates of the point of intersection of these two lines is the solution to the simultaneous equations.
How do you graph the equation y equals -x-3?
Here is a simple way to graph a linear equation. A linear equation is one that has a y term (a number times y), an x term and a constant (but no squares or cubes or square roots etc.): Let x = 0 and use the equation to find y. This gives you one point on the graph: (0, -3) Let y = 0 and use the equation to find x. This gives you another point on the graph (3, 0) Plot these two points, join them with a line and extend in both directions. However, this method gives only one point if the equation is of the form y = ax where a is some non-zero constant; and that point is (0,0) In that case, use (1,a) as the second point.
How do you find the equation for the line of best fit?
There are many ways, but probably you aren't in a statistics class, but in an algebra class. Step 1 plot all the data points on a coordinate plane graph (x-y graph) Step 2 estimate a line 'close' to points. Step 3 use 2 points ON THE LINE (these do not need to be data points) Step 4 find slope of line using points from step 3 Step 5 use point-slope formula to write the equation.
How can you show that two objects are proportional with an equation?
You can use a plot diagram to plot the points and if they all go straight through the origin then it is proportional
